ASVAB Math Knowledge Practice Test 165731 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

Simplify 9a x 6b.

86% Answer Correctly
15ab
54ab
54a2b2
54\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

9a x 6b = (9 x 6) (a x b) = 54ab


2

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

the perimeter of a parallelogram is the sum of the lengths of all sides

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the area of a parallelogram is base x height


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

On this circle, line segment AB is the:

72% Answer Correctly

radius

diameter

circumference

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

The dimensions of this cylinder are height (h) = 9 and radius (r) = 7. What is the volume?

63% Answer Correctly
72π
125π
64π
441π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(72 x 9)
v = 441π


5

If the area of this square is 64, what is the length of one of the diagonals?

69% Answer Correctly
9\( \sqrt{2} \)
8\( \sqrt{2} \)
4\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)