ASVAB Math Knowledge Practice Test 166061 Results

Your Results Global Average
Questions 5 5
Correct 0 2.87
Score 0% 57%

Review

1

Solve for b:
-7b - 8 = \( \frac{b}{2} \)

46% Answer Correctly
-1\(\frac{1}{11}\)
\(\frac{27}{80}\)
-1\(\frac{7}{13}\)
-1\(\frac{1}{15}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-7b - 8 = \( \frac{b}{2} \)
2 x (-7b - 8) = b
(2 x -7b) + (2 x -8) = b
-14b - 16 = b
-14b - 16 - b = 0
-14b - b = 16
-15b = 16
b = \( \frac{16}{-15} \)
b = -1\(\frac{1}{15}\)


2

The dimensions of this trapezoid are a = 4, b = 4, c = 5, d = 9, and h = 2. What is the area?

51% Answer Correctly
16\(\frac{1}{2}\)
13
32
22\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(4 + 9)(2)
a = ½(13)(2)
a = ½(26) = \( \frac{26}{2} \)
a = 13


3

What is 2a - 4a?

80% Answer Correctly
-2a2
8a2
-2a
6

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a - 4a = -2a


4

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c - a

a2 - c2

c2 + a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


5

Simplify (6a)(2ab) - (5a2)(4b).

63% Answer Correctly
-8a2b
32ab2
32a2b
72ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(2ab) - (5a2)(4b)
(6 x 2)(a x a x b) - (5 x 4)(a2 x b)
(12)(a1+1 x b) - (20)(a2b)
12a2b - 20a2b
-8a2b