When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5b - 6b = -2b + 8z + 1 for b in terms of z.
| 3z - 3 | |
| -4\(\frac{2}{3}\)z - \(\frac{1}{3}\) | |
| \(\frac{2}{3}\)z - \(\frac{1}{6}\) | |
| -3\(\frac{1}{2}\)z - 1 |