When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 3c = -c - 4z + 6 for c in terms of z.
| -\(\frac{1}{3}\)z + 1\(\frac{1}{3}\) | |
| -\(\frac{1}{9}\)z + \(\frac{2}{3}\) | |
| \(\frac{8}{13}\)z + \(\frac{6}{13}\) | |
| \(\frac{5}{7}\)z - \(\frac{3}{14}\) |