ASVAB Math Knowledge Practice Test 167961 Results

Your Results Global Average
Questions 5 5
Correct 0 2.81
Score 0% 56%

Review

1

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

acute, obtuse

vertical, supplementary

supplementary, vertical

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


2

Factor y2 - 5y - 6

54% Answer Correctly
(y + 6)(y + 1)
(y + 6)(y - 1)
(y - 6)(y + 1)
(y - 6)(y - 1)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -6 as well and sum (Inside, Outside) to equal -5. For this problem, those two numbers are -6 and 1. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 5y - 6
y2 + (-6 + 1)y + (-6 x 1)
(y - 6)(y + 1)


3

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

68% Answer Correctly

2lw x 2wh + 2lh

h2 x l2 x w2

lw x wh + lh

h x l x w


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


4

Simplify (6a)(3ab) - (3a2)(2b).

62% Answer Correctly
24a2b
24ab2
12a2b
45a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(3ab) - (3a2)(2b)
(6 x 3)(a x a x b) - (3 x 2)(a2 x b)
(18)(a1+1 x b) - (6)(a2b)
18a2b - 6a2b
12a2b


5

Solve 3b + 4b = 6b - 6z + 1 for b in terms of z.

35% Answer Correctly
3\(\frac{1}{3}\)z - \(\frac{1}{3}\)
1\(\frac{3}{7}\)z + \(\frac{5}{7}\)
2\(\frac{3}{4}\)z - 1
-\(\frac{3}{7}\)z - 1\(\frac{2}{7}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

3b + 4z = 6b - 6z + 1
3b = 6b - 6z + 1 - 4z
3b - 6b = -6z + 1 - 4z
-3b = -10z + 1
b = \( \frac{-10z + 1}{-3} \)
b = \( \frac{-10z}{-3} \) + \( \frac{1}{-3} \)
b = 3\(\frac{1}{3}\)z - \(\frac{1}{3}\)