| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
acute, obtuse |
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vertical, supplementary |
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supplementary, vertical |
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obtuse, acute |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Factor y2 - 5y - 6
| (y + 6)(y + 1) | |
| (y + 6)(y - 1) | |
| (y - 6)(y + 1) | |
| (y - 6)(y - 1) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -6 as well and sum (Inside, Outside) to equal -5. For this problem, those two numbers are -6 and 1. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 5y - 6
y2 + (-6 + 1)y + (-6 x 1)
(y - 6)(y + 1)
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
2lw x 2wh + 2lh |
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h2 x l2 x w2 |
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lw x wh + lh |
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h x l x w |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Simplify (6a)(3ab) - (3a2)(2b).
| 24a2b | |
| 24ab2 | |
| 12a2b | |
| 45a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(3ab) - (3a2)(2b)
(6 x 3)(a x a x b) - (3 x 2)(a2 x b)
(18)(a1+1 x b) - (6)(a2b)
18a2b - 6a2b
12a2b
Solve 3b + 4b = 6b - 6z + 1 for b in terms of z.
| 3\(\frac{1}{3}\)z - \(\frac{1}{3}\) | |
| 1\(\frac{3}{7}\)z + \(\frac{5}{7}\) | |
| 2\(\frac{3}{4}\)z - 1 | |
| -\(\frac{3}{7}\)z - 1\(\frac{2}{7}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
3b + 4z = 6b - 6z + 1
3b = 6b - 6z + 1 - 4z
3b - 6b = -6z + 1 - 4z
-3b = -10z + 1
b = \( \frac{-10z + 1}{-3} \)
b = \( \frac{-10z}{-3} \) + \( \frac{1}{-3} \)
b = 3\(\frac{1}{3}\)z - \(\frac{1}{3}\)