When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c - 3c = -6c - 8x - 1 for c in terms of x.
| -\(\frac{1}{6}\)x + \(\frac{1}{12}\) | |
| \(\frac{5}{6}\)x - \(\frac{1}{2}\) | |
| \(\frac{1}{7}\)x + \(\frac{4}{7}\) | |
| -5x - 1 |