| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.32 |
| Score | 0% | 66% |
If a = c = 8, b = d = 2, what is the area of this rectangle?
| 14 | |
| 5 | |
| 16 | |
| 27 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 8 x 2
a = 16
Factor y2 + y - 30
| (y - 5)(y + 6) | |
| (y - 5)(y - 6) | |
| (y + 5)(y + 6) | |
| (y + 5)(y - 6) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -30 as well and sum (Inside, Outside) to equal 1. For this problem, those two numbers are -5 and 6. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + y - 30
y2 + (-5 + 6)y + (-5 x 6)
(y - 5)(y + 6)
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
|
addition |
|
exponents |
|
pairs |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve for a:
-5a + 1 > -4 + 5a
| a > 3\(\frac{1}{2}\) | |
| a > -1\(\frac{1}{3}\) | |
| a > \(\frac{1}{2}\) | |
| a > -1\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-5a + 1 > -4 + 5a
-5a > -4 + 5a - 1
-5a - 5a > -4 - 1
-10a > -5
a > \( \frac{-5}{-10} \)
a > \(\frac{1}{2}\)
The dimensions of this cube are height (h) = 9, length (l) = 7, and width (w) = 7. What is the surface area?
| 350 | |
| 28 | |
| 144 | |
| 80 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 7 x 7) + (2 x 7 x 9) + (2 x 7 x 9)
sa = (98) + (126) + (126)
sa = 350