When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 6c = 4c - 9x + 3 for c in terms of x.
| 1\(\frac{1}{4}\)x + \(\frac{1}{2}\) | |
| -2\(\frac{1}{6}\)x - \(\frac{2}{3}\) | |
| -\(\frac{4}{5}\)x - 1\(\frac{2}{5}\) | |
| 1\(\frac{7}{8}\)x - \(\frac{3}{8}\) |