| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.57 |
| Score | 0% | 51% |
Which of the following is not required to define the slope-intercept equation for a line?
y-intercept |
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slope |
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\({\Delta y \over \Delta x}\) |
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x-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
obtuse, acute |
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supplementary, vertical |
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vertical, supplementary |
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acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Solve for z:
z2 - 15z + 13 = -4z - 5
| 2 or 9 | |
| 6 or -3 | |
| 8 or 4 | |
| 2 or -3 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 - 15z + 13 = -4z - 5
z2 - 15z + 13 + 5 = -4z
z2 - 15z + 4z + 18 = 0
z2 - 11z + 18 = 0
Next, factor the quadratic equation:
z2 - 11z + 18 = 0
(z - 2)(z - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z - 9) must equal zero:
If (z - 2) = 0, z must equal 2
If (z - 9) = 0, z must equal 9
So the solution is that z = 2 or 9
A(n) __________ is to a parallelogram as a square is to a rectangle.
trapezoid |
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rhombus |
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quadrilateral |
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triangle |
A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.
Solve for a:
a + 6 > -3 - 9a
| a > 3 | |
| a > 1 | |
| a > -\(\frac{9}{10}\) | |
| a > \(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
a + 6 > -3 - 9a
a > -3 - 9a - 6
a + 9a > -3 - 6
10a > -9
a > \( \frac{-9}{10} \)
a > -\(\frac{9}{10}\)