When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 2c = -9c - 4z + 2 for c in terms of z.
| -\(\frac{1}{8}\)z - \(\frac{3}{16}\) | |
| -\(\frac{5}{9}\)z + \(\frac{2}{3}\) | |
| -\(\frac{3}{17}\)z - \(\frac{1}{17}\) | |
| -\(\frac{2}{15}\)z + \(\frac{2}{15}\) |