ASVAB Math Knowledge Practice Test 173115 Results

Your Results Global Average
Questions 5 5
Correct 0 3.35
Score 0% 67%

Review

1

This diagram represents two parallel lines with a transversal. If w° = 29, what is the value of y°?

73% Answer Correctly
168
164
151
153

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with w° = 29, the value of y° is 151.


2

What is 2a5 - 2a5?

74% Answer Correctly
0
4
0a5
4a10

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a5 - 2a5 = 0a5


3

Simplify (y + 6)(y + 5)

64% Answer Correctly
y2 - y - 30
y2 + y - 30
y2 + 11y + 30
y2 - 11y + 30

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 6)(y + 5)
(y x y) + (y x 5) + (6 x y) + (6 x 5)
y2 + 5y + 6y + 30
y2 + 11y + 30


4

What is the area of a circle with a diameter of 8?

70% Answer Correctly
16π
25π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{8}{2} \)
r = 4
a = πr2
a = π(42)
a = 16π


5

Factor y2 + 6y - 16

54% Answer Correctly
(y - 2)(y - 8)
(y + 2)(y - 8)
(y - 2)(y + 8)
(y + 2)(y + 8)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -16 as well and sum (Inside, Outside) to equal 6. For this problem, those two numbers are -2 and 8. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 6y - 16
y2 + (-2 + 8)y + (-2 x 8)
(y - 2)(y + 8)