ASVAB Math Knowledge Practice Test 1734 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

What is 3a5 + 9a5?

74% Answer Correctly
-6a10
27a5
27a10
12a5

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a5 + 9a5 = 12a5


2

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

all interior angles are right angles

the area is length x width

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


3

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
\( \sqrt{2} \)
7\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


4

If a = c = 2, b = d = 1, what is the area of this rectangle?

79% Answer Correctly
45
24
12
2

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 2 x 1
a = 2


5

Simplify (2a)(9ab) - (2a2)(2b).

59% Answer Correctly
22a2b
14a2b
44a2b
-14ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(9ab) - (2a2)(2b)
(2 x 9)(a x a x b) - (2 x 2)(a2 x b)
(18)(a1+1 x b) - (4)(a2b)
18a2b - 4a2b
14a2b