When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8b + 6b = -6b + 3z - 3 for b in terms of z.
| -z + \(\frac{2}{3}\) | |
| -\(\frac{4}{7}\)z + \(\frac{5}{14}\) | |
| z - 1 | |
| 1\(\frac{1}{2}\)z + 1\(\frac{1}{2}\) |