| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
A trapezoid is a quadrilateral with one set of __________ sides.
parallel |
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equal length |
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equal angle |
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right angle |
A trapezoid is a quadrilateral with one set of parallel sides.
The dimensions of this trapezoid are a = 5, b = 4, c = 8, d = 4, and h = 3. What is the area?
| 18 | |
| 15 | |
| 12 | |
| 9 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(4 + 4)(3)
a = ½(8)(3)
a = ½(24) = \( \frac{24}{2} \)
a = 12
Solve for y:
y2 - y + 0 = 2y - 2
| 1 or 2 | |
| 1 or -4 | |
| 7 or -2 | |
| 9 or -4 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 - y + 0 = 2y - 2
y2 - y + 0 + 2 = 2y
y2 - y - 2y + 2 = 0
y2 - 3y + 2 = 0
Next, factor the quadratic equation:
y2 - 3y + 2 = 0
(y - 1)(y - 2) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 1) or (y - 2) must equal zero:
If (y - 1) = 0, y must equal 1
If (y - 2) = 0, y must equal 2
So the solution is that y = 1 or 2
Which of the following expressions contains exactly two terms?
binomial |
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quadratic |
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monomial |
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polynomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
If the area of this square is 49, what is the length of one of the diagonals?
| 7\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)