A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a + 4a = 10a

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s²

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c² = a² + b²
c² = 3² + 3²
c² = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a² - 8a + 2 = -2a - 3
a² - 8a + 2 + 3 = -2a
a² - 8a + 2a + 5 = 0
a² - 6a + 5 = 0

Next, factor the quadratic equation:

a² - 6a + 5 = 0
(a - 1)(a - 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 1) or (a - 5) must equal zero:

If (a - 1) = 0, a must equal 1
If (a - 5) = 0, a must equal 5

So the solution is that a = 1 or 5