| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.85 |
| Score | 0% | 57% |
The dimensions of this trapezoid are a = 5, b = 8, c = 7, d = 3, and h = 4. What is the area?
| 22 | |
| 18 | |
| 32\(\frac{1}{2}\) | |
| 21 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(8 + 3)(4)
a = ½(11)(4)
a = ½(44) = \( \frac{44}{2} \)
a = 22
What is 5a3 - 7a3?
| 35a6 | |
| 35a3 | |
| -2a3 | |
| -2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a3 - 7a3 = -2a3
Factor y2 - 5y + 6
| (y + 3)(y - 2) | |
| (y - 3)(y - 2) | |
| (y - 3)(y + 2) | |
| (y + 3)(y + 2) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 6 as well and sum (Inside, Outside) to equal -5. For this problem, those two numbers are -3 and -2. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 5y + 6
y2 + (-3 - 2)y + (-3 x -2)
(y - 3)(y - 2)
What is the area of a circle with a diameter of 6?
| 9π | |
| 7π | |
| 36π | |
| 25π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{6}{2} \)
r = 3
a = πr2
a = π(32)
a = 9π
Solve -6b - 3b = 7b - 3z - 8 for b in terms of z.
| -2\(\frac{2}{5}\)z + 1\(\frac{2}{5}\) | |
| -\(\frac{1}{14}\)z + \(\frac{4}{7}\) | |
| -z - \(\frac{6}{11}\) | |
| z + \(\frac{8}{13}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-6b - 3z = 7b - 3z - 8
-6b = 7b - 3z - 8 + 3z
-6b - 7b = -3z - 8 + 3z
-13b = - 8
b = \( \frac{ - 8}{-13} \)
b = \( \frac{}{-13} \) + \( \frac{-8}{-13} \)
b = z + \(\frac{8}{13}\)