When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 9c = 4c + 6x - 2 for c in terms of x.
| \(\frac{1}{9}\)x - \(\frac{1}{3}\) | |
| \(\frac{1}{4}\)x + \(\frac{1}{6}\) | |
| 1\(\frac{1}{3}\)x + \(\frac{2}{3}\) | |
| -\(\frac{1}{5}\)x - 1\(\frac{4}{5}\) |