When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = -3c - 6z - 6 for c in terms of z.
| -\(\frac{3}{7}\)z - \(\frac{6}{7}\) | |
| \(\frac{3}{10}\)z + \(\frac{7}{10}\) | |
| -\(\frac{5}{6}\)z - \(\frac{1}{3}\) | |
| -8z + 8 |