| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
Which of the following expressions contains exactly two terms?
binomial |
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polynomial |
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quadratic |
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monomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
The endpoints of this line segment are at (-2, 4) and (2, 0). What is the slope-intercept equation for this line?
| y = -2x + 0 | |
| y = -x + 2 | |
| y = 1\(\frac{1}{2}\)x - 3 | |
| y = -1\(\frac{1}{2}\)x + 0 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 4) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (4.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)Plugging these values into the slope-intercept equation:
y = -x + 2
Factor y2 + 5y + 4
| (y - 1)(y + 4) | |
| (y + 1)(y - 4) | |
| (y - 1)(y - 4) | |
| (y + 1)(y + 4) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 4 as well and sum (Inside, Outside) to equal 5. For this problem, those two numbers are 1 and 4. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 5y + 4
y2 + (1 + 4)y + (1 x 4)
(y + 1)(y + 4)
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
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squaring |
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deconstructing |
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normalizing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Simplify (y + 6)(y - 3)
| y2 - 3y - 18 | |
| y2 + 3y - 18 | |
| y2 + 9y + 18 | |
| y2 - 9y + 18 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 6)(y - 3)
(y x y) + (y x -3) + (6 x y) + (6 x -3)
y2 - 3y + 6y - 18
y2 + 3y - 18