| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
Simplify (y + 4)(y + 4)
| y2 - 8y + 16 | |
| y2 + 8y + 16 | |
| 26 | |
| y2 - 16 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 4)(y + 4)
(y x y) + (y x 4) + (4 x y) + (4 x 4)
y2 + 4y + 4y + 16
y2 + 8y + 16
On this circle, line segment AB is the:
diameter |
|
chord |
|
radius |
|
circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
What is 6a3 + 5a3?
| 11a3 | |
| a36 | |
| 11 | |
| a6 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a3 + 5a3 = 11a3
The endpoints of this line segment are at (-2, 6) and (2, 0). What is the slope-intercept equation for this line?
| y = 2\(\frac{1}{2}\)x + 0 | |
| y = -1\(\frac{1}{2}\)x + 3 | |
| y = -2x - 1 | |
| y = 2\(\frac{1}{2}\)x - 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)Plugging these values into the slope-intercept equation:
y = -1\(\frac{1}{2}\)x + 3
Solve for c:
c2 - 4c + 2 = -3c + 4
| 7 or 1 | |
| 7 or -9 | |
| -1 or 2 | |
| 4 or -1 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 - 4c + 2 = -3c + 4
c2 - 4c + 2 - 4 = -3c
c2 - 4c + 3c - 2 = 0
c2 - c - 2 = 0
Next, factor the quadratic equation:
c2 - c - 2 = 0
(c + 1)(c - 2) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 1) or (c - 2) must equal zero:
If (c + 1) = 0, c must equal -1
If (c - 2) = 0, c must equal 2
So the solution is that c = -1 or 2