ASVAB Math Knowledge Practice Test 178728

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5a + 6a = -3a - 3z + 3 for a in terms of z.

2\(\frac{1}{5}\)z + \(\frac{3}{5}\)
-1\(\frac{1}{8}\)z + \(\frac{3}{8}\)
-1\(\frac{1}{3}\)z + 2
3\(\frac{1}{3}\)z - 2\(\frac{1}{3}\)