When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8b + 4b = 5b + 5z - 6 for b in terms of z.
| -\(\frac{1}{2}\)z + \(\frac{5}{14}\) | |
| -2z + \(\frac{1}{6}\) | |
| -\(\frac{1}{11}\)z - \(\frac{2}{11}\) | |
| \(\frac{1}{3}\)z - 2 |