ASVAB Math Knowledge Practice Test 178788 Results

Your Results Global Average
Questions 5 5
Correct 0 2.84
Score 0% 57%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

π r2h2

4π r2

π r2h

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

A right angle measures:

89% Answer Correctly

90°

180°

360°

45°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


3

Find the value of a:
9a + y = 2
a + 6y = 5

41% Answer Correctly
\(\frac{7}{53}\)
-1\(\frac{3}{17}\)
-\(\frac{9}{17}\)
\(\frac{22}{37}\)

Solution

You need to find the value of a so solve the first equation in terms of y:

9a + y = 2
y = 2 - 9a

then substitute the result (2 - 9a) into the second equation:

a + 6(2 - 9a) = 5
a + (6 x 2) + (6 x -9a) = 5
a + 12 - 54a = 5
a - 54a = 5 - 12
-53a = -7
a = \( \frac{-7}{-53} \)
a = \(\frac{7}{53}\)


4

Solve for a:
a - 7 = \( \frac{a}{-1} \)

46% Answer Correctly
3\(\frac{1}{2}\)
\(\frac{9}{28}\)
\(\frac{24}{29}\)
\(\frac{14}{15}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

a - 7 = \( \frac{a}{-1} \)
-1 x (a - 7) = a
(-1 x a) + (-1 x -7) = a
-a + 7 = a
-a + 7 - a = 0
-a - a = -7
-2a = -7
a = \( \frac{-7}{-2} \)
a = 3\(\frac{1}{2}\)


5

Factor y2 + 8y + 15

53% Answer Correctly
(y + 3)(y - 5)
(y - 3)(y - 5)
(y + 3)(y + 5)
(y - 3)(y + 5)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 15 as well and sum (Inside, Outside) to equal 8. For this problem, those two numbers are 3 and 5. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 8y + 15
y2 + (3 + 5)y + (3 x 5)
(y + 3)(y + 5)