When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = -5c - 6x + 2 for c in terms of x.
| -\(\frac{13}{15}\)x - \(\frac{1}{5}\) | |
| -3x - 1\(\frac{2}{5}\) | |
| -\(\frac{1}{3}\)x + \(\frac{2}{9}\) | |
| 3\(\frac{1}{3}\)x - 3 |