ASVAB Math Knowledge Practice Test 182400 Results

Your Results Global Average
Questions 5 5
Correct 0 2.82
Score 0% 56%

Review

1

Simplify (6a)(5ab) - (9a2)(4b).

59% Answer Correctly
143a2b
66ab2
-6a2b
143ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(5ab) - (9a2)(4b)
(6 x 5)(a x a x b) - (9 x 4)(a2 x b)
(30)(a1+1 x b) - (36)(a2b)
30a2b - 36a2b
-6a2b


2

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

supplementary, vertical

obtuse, acute

vertical, supplementary

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


3

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
2\( \sqrt{2} \)
8\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


4

Which types of triangles will always have at least two sides of equal length?

53% Answer Correctly

equilateral and right

equilateral, isosceles and right

equilateral and isosceles

isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


5

Find the value of a:
-9a + y = -7
-5a - 6y = -5

42% Answer Correctly
6\(\frac{7}{10}\)
\(\frac{7}{19}\)
2\(\frac{16}{23}\)
\(\frac{47}{59}\)

Solution

You need to find the value of a so solve the first equation in terms of y:

-9a + y = -7
y = -7 + 9a

then substitute the result (-7 - -9a) into the second equation:

-5a - 6(-7 + 9a) = -5
-5a + (-6 x -7) + (-6 x 9a) = -5
-5a + 42 - 54a = -5
-5a - 54a = -5 - 42
-59a = -47
a = \( \frac{-47}{-59} \)
a = \(\frac{47}{59}\)