| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
Simplify (6a)(5ab) - (9a2)(4b).
| 143a2b | |
| 66ab2 | |
| -6a2b | |
| 143ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(5ab) - (9a2)(4b)
(6 x 5)(a x a x b) - (9 x 4)(a2 x b)
(30)(a1+1 x b) - (36)(a2b)
30a2b - 36a2b
-6a2b
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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obtuse, acute |
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vertical, supplementary |
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acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
If the area of this square is 25, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
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equilateral, isosceles and right |
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equilateral and isosceles |
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isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Find the value of a:
-9a + y = -7
-5a - 6y = -5
| 6\(\frac{7}{10}\) | |
| \(\frac{7}{19}\) | |
| 2\(\frac{16}{23}\) | |
| \(\frac{47}{59}\) |
You need to find the value of a so solve the first equation in terms of y:
-9a + y = -7
y = -7 + 9a
then substitute the result (-7 - -9a) into the second equation:
-5a - 6(-7 + 9a) = -5
-5a + (-6 x -7) + (-6 x 9a) = -5
-5a + 42 - 54a = -5
-5a - 54a = -5 - 42
-59a = -47
a = \( \frac{-47}{-59} \)
a = \(\frac{47}{59}\)