ASVAB Math Knowledge Practice Test 182728

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c + 8c = 5c - y - 5 for c in terms of y.

-9y - 5
\(\frac{7}{8}\)y + \(\frac{1}{8}\)
5\(\frac{2}{3}\)y - \(\frac{1}{3}\)
-\(\frac{12}{13}\)y - \(\frac{9}{13}\)