ASVAB Math Knowledge Practice Test 184564

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c - 5c = 6c + 6x + 3 for c in terms of x.

6\(\frac{1}{2}\)x - 3
2x + 8
-2\(\frac{1}{5}\)x - \(\frac{3}{5}\)
-\(\frac{4}{5}\)x - \(\frac{2}{5}\)