When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 9c = 4c - 5x + 5 for c in terms of x.
| 6\(\frac{1}{2}\)x - 3 | |
| x - 1\(\frac{1}{2}\) | |
| -14x + 5 | |
| \(\frac{1}{3}\)x + \(\frac{2}{9}\) |