When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + c = 8c + 2x + 4 for c in terms of x.
| -\(\frac{1}{3}\)x - 1\(\frac{1}{3}\) | |
| 2x - 3 | |
| \(\frac{1}{3}\)x - \(\frac{1}{6}\) | |
| \(\frac{1}{18}\)x + \(\frac{1}{2}\) |