When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = -6c - 9x + 3 for c in terms of x.
| -1\(\frac{1}{5}\)x + \(\frac{3}{10}\) | |
| 4\(\frac{1}{4}\)x - 2 | |
| 1\(\frac{1}{8}\)x + \(\frac{3}{4}\) | |
| 2\(\frac{1}{2}\)x + 2\(\frac{1}{2}\) |