| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.68 |
| Score | 0% | 54% |
Which of the following statements about a triangle is not true?
sum of interior angles = 180° |
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area = ½bh |
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exterior angle = sum of two adjacent interior angles |
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perimeter = sum of side lengths |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Which of the following is not true about both rectangles and squares?
all interior angles are right angles |
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the area is length x width |
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the lengths of all sides are equal |
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the perimeter is the sum of the lengths of all four sides |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
Solve for z:
-9z - 6 = 4 - 6z
| -\(\frac{1}{2}\) | |
| \(\frac{2}{7}\) | |
| -3\(\frac{1}{3}\) | |
| -2\(\frac{1}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-9z - 6 = 4 - 6z
-9z = 4 - 6z + 6
-9z + 6z = 4 + 6
-3z = 10
z = \( \frac{10}{-3} \)
z = -3\(\frac{1}{3}\)
Find the value of b:
5b + z = -5
-3b - 9z = 7
| 1\(\frac{7}{38}\) | |
| -\(\frac{4}{21}\) | |
| -\(\frac{19}{21}\) | |
You need to find the value of b so solve the first equation in terms of z:
5b + z = -5
z = -5 - 5b
then substitute the result (-5 - 5b) into the second equation:
-3b - 9(-5 - 5b) = 7
-3b + (-9 x -5) + (-9 x -5b) = 7
-3b + 45 + 45b = 7
-3b + 45b = 7 - 45
42b = -38
b = \( \frac{-38}{42} \)
b = -\(\frac{19}{21}\)
Solve for c:
c + 5 = \( \frac{c}{-2} \)
| \(\frac{32}{65}\) | |
| -\(\frac{18}{47}\) | |
| -3\(\frac{1}{3}\) | |
| -2\(\frac{4}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
c + 5 = \( \frac{c}{-2} \)
-2 x (c + 5) = c
(-2 x c) + (-2 x 5) = c
-2c - 10 = c
-2c - 10 - c = 0
-2c - c = 10
-3c = 10
c = \( \frac{10}{-3} \)
c = -3\(\frac{1}{3}\)