When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 2c = 4c + 6x - 1 for c in terms of x.
| -\(\frac{1}{3}\)x + \(\frac{1}{12}\) | |
| x - 1\(\frac{1}{4}\) | |
| -\(\frac{1}{4}\)x - 1\(\frac{1}{2}\) | |
| 6x - 6 |