When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 6c = -5c + 7x - 3 for c in terms of x.
| -4\(\frac{1}{2}\)x + 3 | |
| -10x + 7 | |
| 12x - 4 | |
| -\(\frac{1}{3}\)x + 1 |