ASVAB Math Knowledge Practice Test 190168

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6b - 5b = -3b - z - 2 for b in terms of z.

z + 1
\(\frac{4}{9}\)z - \(\frac{2}{9}\)
z + 2\(\frac{1}{3}\)
3\(\frac{1}{2}\)z + 3