ASVAB Math Knowledge Practice Test 190192

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve b + 6b = -4b + 6x - 3 for b in terms of x.

x - \(\frac{3}{5}\)
\(\frac{3}{8}\)x - \(\frac{3}{4}\)
2\(\frac{2}{3}\)x - 2\(\frac{1}{3}\)
-x + \(\frac{3}{5}\)