ASVAB Math Knowledge Practice Test 190606 Results

Your Results Global Average
Questions 5 5
Correct 0 3.39
Score 0% 68%

Review

1

This diagram represents two parallel lines with a transversal. If y° = 145, what is the value of w°?

73% Answer Correctly
10
38
18
35

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with y° = 145, the value of w° is 35.


2

If a = 2, b = 2, c = 9, and d = 6, what is the perimeter of this quadrilateral?

88% Answer Correctly
29
19
20
23

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 2 + 2 + 9 + 6
p = 19


3

Solve for b:
3b - 5 = -9 - 4b

59% Answer Correctly
-\(\frac{1}{3}\)
\(\frac{2}{3}\)
-\(\frac{4}{7}\)
1\(\frac{1}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

3b - 5 = -9 - 4b
3b = -9 - 4b + 5
3b + 4b = -9 + 5
7b = -4
b = \( \frac{-4}{7} \)
b = -\(\frac{4}{7}\)


4

Order the following types of angle from least number of degrees to most number of degrees.

75% Answer Correctly

right, obtuse, acute

right, acute, obtuse

acute, obtuse, right

acute, right, obtuse


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


5

Solve for x:
7x - 1 = \( \frac{x}{-2} \)

46% Answer Correctly
-\(\frac{4}{17}\)
4\(\frac{4}{5}\)
-\(\frac{28}{37}\)
\(\frac{2}{15}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

7x - 1 = \( \frac{x}{-2} \)
-2 x (7x - 1) = x
(-2 x 7x) + (-2 x -1) = x
-14x + 2 = x
-14x + 2 - x = 0
-14x - x = -2
-15x = -2
x = \( \frac{-2}{-15} \)
x = \(\frac{2}{15}\)