When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 6c = 2c - 8z - 7 for c in terms of z.
| -\(\frac{1}{3}\)z - 1\(\frac{1}{6}\) | |
| \(\frac{3}{4}\)z + \(\frac{1}{3}\) | |
| -z + 5 | |
| -\(\frac{4}{5}\)z - \(\frac{3}{5}\) |