When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 5c = 4c + 3z - 2 for c in terms of z.
| \(\frac{4}{5}\)z + \(\frac{3}{5}\) | |
| -2z + 4 | |
| -\(\frac{1}{6}\)z - \(\frac{7}{12}\) | |
| 4z - 1 |