ASVAB Math Knowledge Practice Test 191538

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4a + 4a = a + 5z - 5 for a in terms of z.

-2\(\frac{1}{2}\)z + 2\(\frac{1}{2}\)
-\(\frac{1}{3}\)z - \(\frac{1}{4}\)
-\(\frac{1}{5}\)z + 1
-1\(\frac{5}{11}\)z + \(\frac{2}{11}\)