ASVAB Math Knowledge Practice Test 191594

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6b - 6b = 2b - 4z - 8 for b in terms of z.

\(\frac{2}{3}\)z - 1
\(\frac{4}{5}\)z + 1\(\frac{3}{5}\)
\(\frac{1}{2}\)z - 2
-2z - 3