ASVAB Math Knowledge Practice Test 191965 Results

Your Results Global Average
Questions 5 5
Correct 0 3.47
Score 0% 69%

Review

1

If side x = 6cm, side y = 15cm, and side z = 15cm what is the perimeter of this triangle?

84% Answer Correctly
36cm
32cm
35cm
42cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 6cm + 15cm + 15cm = 36cm


2

Simplify 7a x 8b.

86% Answer Correctly
56\( \frac{a}{b} \)
56ab
56\( \frac{b}{a} \)
15ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

7a x 8b = (7 x 8) (a x b) = 56ab


3

If the base of this triangle is 2 and the height is 9, what is the area?

58% Answer Correctly
78
9
36
63

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 2 x 9 = \( \frac{18}{2} \) = 9


4

This diagram represents two parallel lines with a transversal. If a° = 15, what is the value of x°?

73% Answer Correctly
34
10
165
143

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with a° = 15, the value of x° is 165.


5

Solve for a:
-8a - 6 = \( \frac{a}{4} \)

46% Answer Correctly
1\(\frac{7}{9}\)
1
-\(\frac{8}{11}\)
-\(\frac{4}{33}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-8a - 6 = \( \frac{a}{4} \)
4 x (-8a - 6) = a
(4 x -8a) + (4 x -6) = a
-32a - 24 = a
-32a - 24 - a = 0
-32a - a = 24
-33a = 24
a = \( \frac{24}{-33} \)
a = -\(\frac{8}{11}\)