When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 5c = 2c + 8z + 2 for c in terms of z.
| 6\(\frac{1}{2}\)z + 1 | |
| z + 2 | |
| 3\(\frac{1}{4}\)z - 1 | |
| 2\(\frac{1}{3}\)z + 1\(\frac{1}{3}\) |