ASVAB Math Knowledge Practice Test 192994 Results

Your Results Global Average
Questions 5 5
Correct 0 2.86
Score 0% 57%

Review

1

What is 9a + 9a?

81% Answer Correctly
18a
18a2
0
81a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

9a + 9a = 18a


2

The endpoints of this line segment are at (-2, 2) and (2, 4). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -1\(\frac{1}{2}\)x - 2
y = \(\frac{1}{2}\)x + 0
y = -3x + 4
y = \(\frac{1}{2}\)x + 3

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 2) and (2, 4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (2.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = \(\frac{1}{2}\)x + 3


3

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π r

c = π r2

c = π d

c = π d2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


4

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

4

3

2

5


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


5

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c - a

c2 - a2

a2 - c2

c2 + a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)