ASVAB Math Knowledge Practice Test 193776

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -a - 2a = 4a + 6z + 6 for a in terms of z.

-1\(\frac{3}{5}\)z - 1\(\frac{1}{5}\)
-\(\frac{3}{5}\)z - \(\frac{7}{10}\)
\(\frac{1}{3}\)z + 1
z + \(\frac{9}{13}\)