Your Results | Global Average | |
---|---|---|
Questions | 5 | 5 |
Correct | 0 | 3.11 |
Score | 0% | 62% |
The dimensions of this cylinder are height (h) = 8 and radius (r) = 1. What is the surface area?
288π | |
54π | |
120π | |
18π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 8)
sa = 2π(1) + 2π(8)
sa = (2 x 1)π + (2 x 8)π
sa = 2π + 16π
sa = 18π
On this circle, a line segment connecting point A to point D is called:
diameter |
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radius |
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chord |
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circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve for a:
2a + 5 < -9 - 3a
a < -\(\frac{1}{8}\) | |
a < -2\(\frac{4}{5}\) | |
a < \(\frac{5}{6}\) | |
a < \(\frac{5}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
2a + 5 < -9 - 3a
2a < -9 - 3a - 5
2a + 3a < -9 - 5
5a < -14
a < \( \frac{-14}{5} \)
a < -2\(\frac{4}{5}\)
Simplify (7a)(7ab) + (8a2)(4b).
-17a2b | |
17a2b | |
81a2b | |
168ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(7ab) + (8a2)(4b)
(7 x 7)(a x a x b) + (8 x 4)(a2 x b)
(49)(a1+1 x b) + (32)(a2b)
49a2b + 32a2b
81a2b
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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exponents |
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pairs |
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addition |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)