ASVAB Math Knowledge Practice Test 195321 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

trisects

intersects

midpoints

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


2

If a = 9, b = 7, c = 9, and d = 9, what is the perimeter of this quadrilateral?

88% Answer Correctly
20
14
29
34

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 9 + 7 + 9 + 9
p = 34


3

Solve for z:
z + 7 < \( \frac{z}{8} \)

44% Answer Correctly
z < -8
z < -1\(\frac{2}{7}\)
z < \(\frac{2}{9}\)
z < -1\(\frac{9}{11}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

z + 7 < \( \frac{z}{8} \)
8 x (z + 7) < z
(8 x z) + (8 x 7) < z
8z + 56 < z
8z + 56 - z < 0
8z - z < -56
7z < -56
z < \( \frac{-56}{7} \)
z < -8


4

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
\( \sqrt{2} \)
4\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)


5

Which of the following statements about math operations is incorrect?

70% Answer Correctly

you can add monomials that have the same variable and the same exponent

you can subtract monomials that have the same variable and the same exponent

all of these statements are correct

you can multiply monomials that have different variables and different exponents


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.