When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 2c = -7c + 4z + 1 for c in terms of z.
| -10z - 4 | |
| \(\frac{2}{15}\)z + \(\frac{1}{15}\) | |
| \(\frac{3}{8}\)z - \(\frac{1}{4}\) | |
| -\(\frac{1}{2}\)z + \(\frac{1}{2}\) |