When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 9c = 6c + 6x - 1 for c in terms of x.
| -\(\frac{3}{10}\)x + \(\frac{2}{5}\) | |
| -2x - 1 | |
| \(\frac{3}{14}\)x + \(\frac{1}{14}\) | |
| x + \(\frac{2}{3}\) |