When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 4c = 8c - 9z + 4 for c in terms of z.
| 6\(\frac{1}{2}\)z + 3\(\frac{1}{2}\) | |
| 4\(\frac{1}{3}\)z - 1\(\frac{1}{3}\) | |
| -1\(\frac{1}{5}\)z + \(\frac{4}{5}\) | |
| -14z + 6 |