ASVAB Math Knowledge Practice Test 196269

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + 3a = 8a - z - 9 for a in terms of z.

-2\(\frac{3}{5}\)z + 1
\(\frac{5}{9}\)z + \(\frac{4}{9}\)
-3\(\frac{1}{3}\)z + 2\(\frac{1}{3}\)
2z + 4\(\frac{1}{2}\)